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Buckley-Leverett two-phase problem ​

Introduction   Validation   Immiscible  

The Buckley-Leverett test problem is a classical reservoir simulation benchmark that demonstrates the nonlinear displacement process of a viscous fluid being displaced by a less viscous fluid, typically taken to be water displacing oil.

Problem definition ​

This is a simple model without wells, where the flow is driven by a simple source term and a simple constant pressure boundary condition at the outlet. We define a function that sets up a two-phase system, a simple 1D domain and replaces the default relative permeability functions with quadratic functions:

krα(S)=min(S−Sr1−Sr,1)n,Sr=0.2,n=2

In addition, the phase viscosities are treated as constant parameters of 1 and 5 centipoise for the displacing and resident fluids, respectively.

The function is parametrized on the number of cells and the number of time-steps used to solve the model. This function, since it uses a relatively simple setup without wells, uses the Jutul functions directly.

julia
using JutulDarcy, Jutul
function solve_bl(;nc = 100, time = 1.0, nstep = nc)
    T = time
    tstep = repeat([T/nstep], nstep)
    domain = get_1d_reservoir(nc)
    nc = number_of_cells(domain)
    timesteps = tstep*3600*24
    bar = 1e5
    p0 = 100*bar
    sys = ImmiscibleSystem((LiquidPhase(), VaporPhase()))
    model = SimulationModel(domain, sys)
    kr = BrooksCoreyRelativePermeabilities(sys, [2.0, 2.0], [0.2, 0.2])
    replace_variables!(model, RelativePermeabilities = kr)
    tot_time = sum(timesteps)
    pv = pore_volume(domain)
    irate = 500*sum(pv)/tot_time
    src  = SourceTerm(1, irate, fractional_flow = [1.0, 0.0])
    bc = FlowBoundaryCondition(nc, p0/2)
    forces = setup_forces(model, sources = src, bc = bc)
    parameters = setup_parameters(model, PhaseViscosities = [1e-3, 5e-3]) # 1 and 5 cP
    state0 = setup_state(model, Pressure = p0, Saturations = [0.0, 1.0])
    states, report = simulate(state0, model, timesteps,
        forces = forces, parameters = parameters)
    return states, model, report
end
solve_bl (generic function with 1 method)

Run the base case ​

We solve a small model with 100 cells and 100 steps to serve as the baseline.

julia
n, n_f = 100, 1000
states, model, report = solve_bl(nc = n)
print_stats(report)
Jutul: Simulating 1 day as 100 report steps
╭────────────────┬───────────┬───────────────┬──────────╮
│ Iteration type │  Avg/step │  Avg/ministep │    Total │
│                │ 100 steps │ 100 ministeps │ (wasted) │
├────────────────┼───────────┼───────────────┼──────────┤
│ Newton         │      4.13 │          4.13 │  413 (0) │
│ Linearization  │      5.13 │          5.13 │  513 (0) │
│ Linear solver  │      4.13 │          4.13 │  413 (0) │
│ Precond apply  │       0.0 │           0.0 │    0 (0) │
╰────────────────┴───────────┴───────────────┴──────────╯
╭───────────────┬────────┬────────────┬────────╮
│ Timing type   │   Each │   Relative │  Total │
│               │     ms │ Percentage │      s │
├───────────────┼────────┼────────────┼────────┤
│ Properties    │ 0.0090 │     0.15 % │ 0.0037 │
│ Equations     │ 0.7119 │    15.03 % │ 0.3652 │
│ Assembly      │ 0.2074 │     4.38 % │ 0.1064 │
│ Linear solve  │ 1.6031 │    27.25 % │ 0.6621 │
│ Linear setup  │ 0.0000 │     0.00 % │ 0.0000 │
│ Precond apply │ 0.0000 │     0.00 % │ 0.0000 │
│ Update        │ 0.0077 │     0.13 % │ 0.0032 │
│ Convergence   │ 0.1927 │     4.07 % │ 0.0988 │
│ Input/Output  │ 0.2496 │     1.03 % │ 0.0250 │
│ Other         │ 2.8208 │    47.95 % │ 1.1650 │
├───────────────┼────────┼────────────┼────────┤
│ Total         │ 5.8822 │   100.00 % │ 2.4294 │
╰───────────────┴────────┴────────────┴────────╯
╭────────────────┬───────────┬───────────────┬──────────╮
│ Iteration type │  Avg/step │  Avg/ministep │    Total │
│                │ 100 steps │ 100 ministeps │ (wasted) │
├────────────────┼───────────┼───────────────┼──────────┤
│ Newton         │      4.13 │          4.13 │  413 (0) │
│ Linearization  │      5.13 │          5.13 │  513 (0) │
│ Linear solver  │      4.13 │          4.13 │  413 (0) │
│ Precond apply  │       0.0 │           0.0 │    0 (0) │
╰────────────────┴───────────┴───────────────┴──────────╯
╭───────────────┬────────┬────────────┬────────╮
│ Timing type   │   Each │   Relative │  Total │
│               │     ms │ Percentage │      s │
├───────────────┼────────┼────────────┼────────┤
│ Properties    │ 0.0090 │     0.15 % │ 0.0037 │
│ Equations     │ 0.7119 │    15.03 % │ 0.3652 │
│ Assembly      │ 0.2074 │     4.38 % │ 0.1064 │
│ Linear solve  │ 1.6031 │    27.25 % │ 0.6621 │
│ Linear setup  │ 0.0000 │     0.00 % │ 0.0000 │
│ Precond apply │ 0.0000 │     0.00 % │ 0.0000 │
│ Update        │ 0.0077 │     0.13 % │ 0.0032 │
│ Convergence   │ 0.1927 │     4.07 % │ 0.0988 │
│ Input/Output  │ 0.2496 │     1.03 % │ 0.0250 │
│ Other         │ 2.8208 │    47.95 % │ 1.1650 │
├───────────────┼────────┼────────────┼────────┤
│ Total         │ 5.8822 │   100.00 % │ 2.4294 │
╰───────────────┴────────┴────────────┴────────╯

Run refined version (1000 cells, 1000 steps) ​

Using a grid with 100 cells will not yield a fully converged solution. We can increase the number of cells at the cost of increasing the runtime a bit. Note that most of the time is spent in the linear solver, which uses a direct sparse LU factorization by default. For larger problems it is recommended to use an iterative solver. The high-level interface used in later examples automatically sets up an iterative solver with the appropriate preconditioner.

julia
states_refined, _, report_refined = solve_bl(nc = n_f);
print_stats(report_refined)
Jutul: Simulating 1 day, 0.0291 nanoseconds as 1000 report steps
╭────────────────┬────────────┬────────────────┬──────────╮
│ Iteration type │   Avg/step │   Avg/ministep │    Total │
│                │ 1000 steps │ 1000 ministeps │ (wasted) │
├────────────────┼────────────┼────────────────┼──────────┤
│ Newton         │       4.12 │           4.12 │ 4120 (0) │
│ Linearization  │       5.12 │           5.12 │ 5120 (0) │
│ Linear solver  │       4.12 │           4.12 │ 4120 (0) │
│ Precond apply  │        0.0 │            0.0 │    0 (0) │
╰────────────────┴────────────┴────────────────┴──────────╯
╭───────────────┬────────┬────────────┬────────╮
│ Timing type   │   Each │   Relative │  Total │
│               │     ms │ Percentage │      s │
├───────────────┼────────┼────────────┼────────┤
│ Properties    │ 0.0509 │     2.78 % │ 0.2096 │
│ Equations     │ 0.0273 │     1.85 % │ 0.1396 │
│ Assembly      │ 0.0126 │     0.85 % │ 0.0644 │
│ Linear solve  │ 1.6390 │    89.55 % │ 6.7525 │
│ Linear setup  │ 0.0000 │     0.00 % │ 0.0000 │
│ Precond apply │ 0.0000 │     0.00 % │ 0.0000 │
│ Update        │ 0.0201 │     1.10 % │ 0.0829 │
│ Convergence   │ 0.0218 │     1.48 % │ 0.1115 │
│ Input/Output  │ 0.0342 │     0.45 % │ 0.0342 │
│ Other         │ 0.0354 │     1.93 % │ 0.1457 │
├───────────────┼────────┼────────────┼────────┤
│ Total         │ 1.8302 │   100.00 % │ 7.5403 │
╰───────────────┴────────┴────────────┴────────╯
╭────────────────┬────────────┬────────────────┬──────────╮
│ Iteration type │   Avg/step │   Avg/ministep │    Total │
│                │ 1000 steps │ 1000 ministeps │ (wasted) │
├────────────────┼────────────┼────────────────┼──────────┤
│ Newton         │       4.12 │           4.12 │ 4120 (0) │
│ Linearization  │       5.12 │           5.12 │ 5120 (0) │
│ Linear solver  │       4.12 │           4.12 │ 4120 (0) │
│ Precond apply  │        0.0 │            0.0 │    0 (0) │
╰────────────────┴────────────┴────────────────┴──────────╯
╭───────────────┬────────┬────────────┬────────╮
│ Timing type   │   Each │   Relative │  Total │
│               │     ms │ Percentage │      s │
├───────────────┼────────┼────────────┼────────┤
│ Properties    │ 0.0509 │     2.78 % │ 0.2096 │
│ Equations     │ 0.0273 │     1.85 % │ 0.1396 │
│ Assembly      │ 0.0126 │     0.85 % │ 0.0644 │
│ Linear solve  │ 1.6390 │    89.55 % │ 6.7525 │
│ Linear setup  │ 0.0000 │     0.00 % │ 0.0000 │
│ Precond apply │ 0.0000 │     0.00 % │ 0.0000 │
│ Update        │ 0.0201 │     1.10 % │ 0.0829 │
│ Convergence   │ 0.0218 │     1.48 % │ 0.1115 │
│ Input/Output  │ 0.0342 │     0.45 % │ 0.0342 │
│ Other         │ 0.0354 │     1.93 % │ 0.1457 │
├───────────────┼────────┼────────────┼────────┤
│ Total         │ 1.8302 │   100.00 % │ 7.5403 │
╰───────────────┴────────┴────────────┴────────╯

Plot results ​

We plot the saturation front for the base case at different times together with the final solution for the refined model. In this case, refining the grid by a factor 10 gave us significantly less smearing of the trailing front.

julia
using GLMakie
x = range(0, stop = 1, length = n)
x_f = range(0, stop = 1, length = n_f)
f = Figure()
ax = Axis(f[1, 1], ylabel = "Saturation", title = "Buckley-Leverett displacement")
for i in 1:6:length(states)
    lines!(ax, x, states[i][:Saturations][1, :], color = :darkgray)
end
lines!(ax, x_f, states_refined[end][:Saturations][1, :], color = :red)
f

Example on GitHub ​

If you would like to run this example yourself, it can be downloaded from the JutulDarcy.jl GitHub repository as a script

This example took 14.603327128 seconds to complete.

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